Replacement Method: Formula, Rules and Solved Questions

Replacement Method is used when a part of a liquid mixture is removed and replaced with another liquid, usually water. The method finds the quantity of the original liquid left after one or more operations. Its main formula uses the fraction of the mixture remaining after each replacement and extends directly to repeated replacement.

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What is the Replacement Method?

The Replacement Method calculates the quantity of an original liquid left in a vessel after a fixed quantity is removed and replaced with another liquid. If the vessel volume is V and q is replaced each time, the original quantity after n operations is multiplied by (1 − q/V)^n.

In every operation, the fraction of the original mixture that remains is (V − q)/V. Therefore, if the initial quantity of the original liquid is A, the quantity left after n identical replacements is A[(V − q)/V]^n. This method assumes that the mixture is uniform before each quantity is removed. For example, from a 20-litre vessel, removing and replacing 5 litres twice leaves 20 × (15/20)^2 = 11.25 litres of the original liquid.

Replacement Method Formula & Tricks

Important Formulas

Fraction remaining in one replacement
Fraction remaining = (V − q) / V = 1 − q/V

V is the total volume of the vessel and q is the quantity removed and replaced in one operation.

Original liquid after repeated replacement
A_n = A[(V − q)/V]^n

A is the initial quantity of the original liquid, and n is the number of identical replacement operations.

Original liquid removed
Quantity removed = A − A_n

Subtract the quantity of original liquid left after replacement from its initial quantity.

Replacement when quantities vary
A_n = A × ∏(1 − q_i/V)

If different quantities q₁, q₂, ..., q_n are removed in successive operations, multiply the remaining fractions for all operations.

Quick Tricks

Use the remaining fraction, not the removed fraction

If q/V of the mixture is removed, the fraction left is 1 − q/V. Raise this remaining fraction to the number of identical operations.

Example: If 1/4 of the mixture is replaced in each operation, 3 operations leave (3/4)^3 = 27/64 of the original liquid.
Find the final concentration directly

When the original liquid is pure and the added liquid contains none of it, the final concentration of the original liquid is the remaining fraction multiplied by its initial concentration.

Example: Replacing 20% of a mixture twice leaves 0.8² = 0.64, or 64%, of the original liquid concentration.
For different replacements, multiply separately

Do not add different removed quantities before calculating. Apply each operation successively using its own remaining fraction.

Example: If 1/5 is removed first and 1/4 next, the original fraction left is (4/5)(3/4) = 3/5.

Replacement Method Concepts

Single Replacement in a Uniform Mixture

After removing q units from a uniformly mixed vessel of volume V, the fraction of every component left is (V − q)/V.

If a vessel contains A units of the original liquid, the amount of that liquid removed is Aq/V. Hence, the amount left is A − Aq/V = A(V − q)/V. The same fraction applies to each component of the mixture.

Example: A 30-litre mixture contains 18 litres of milk. If 6 litres are removed and replaced with water, milk left = 18 × (30 − 6)/30 = 14.4 litres.

Repeated Replacement Formula

For the same quantity q removed and replaced n times from a vessel of volume V, the original liquid left is A[(V − q)/V]^n.

After the first operation, the original quantity becomes A(V − q)/V. Each later operation multiplies the current quantity by the same fraction. Therefore, repeated replacement forms a geometric progression.

Example: A vessel has 20 litres of milk. Removing and replacing 5 litres twice leaves 20 × (15/20)^2 = 11.25 litres of milk.

Quantity of New Liquid Added

The quantity of new liquid present after replacement equals the vessel volume minus the quantity of the original liquid left, when the vessel initially contains only the original liquid.

If the initial vessel volume is V and the original liquid remaining after n operations is A_n, then new liquid = V − A_n when A = V initially. If the initial mixture already contains other components, calculate the new liquid component separately from its initial amount and its remaining fraction.

Example: A 20-litre vessel initially contains milk. After two replacements of 5 litres, milk left is 11.25 litres, so water present is 20 − 11.25 = 8.75 litres.

Replacement with Different Quantities

When the removed quantities differ, multiply the remaining fraction for each operation: A_n = A(1 − q₁/V)(1 − q₂/V) ... (1 − q_n/V).

The vessel volume remains V after every replacement, but the fraction removed can change. Each operation acts on the quantity left after the previous operation, so the factors must be applied successively.

Example: From a 20-litre vessel, replace 4 litres first and 5 litres next. The original fraction left is (16/20)(15/20) = 3/5. If the initial original quantity is 20 litres, 12 litres remain.

Finding the Number of Replacements

If the final original quantity is known, use A_n/A = [(V − q)/V]^n and solve for n.

For identical operations, the equation is (1 − q/V)^n = A_n/A. When the value is a simple power, n can be found by inspection. For other values, logarithms may be used: n = log(A_n/A) ÷ log(1 − q/V).

Example: If one-fourth of a mixture is replaced each time and 27/64 of the original liquid remains, then (3/4)^n = (3/4)^3, so n = 3.

Replacement Method Video Lessons

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Repeated Dilution Formula in Replacement

Learn the repeated dilution formula used in replacement method problems, including how successive removals and refills change the concentration or quantity of a mixture.

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Practice Replacement Method Questions

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Replacement Method Quick Quiz

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Quick Revision Notes

Replacement Method Revision Points

Use these rules to solve mixture replacement questions quickly and accurately.

  • For vessel volume V and quantity q replaced each time, the remaining fraction is (V − q)/V.
  • After n identical replacements, original quantity left = A[(V − q)/V]^n.
  • The mixture must be uniform before each quantity is removed.
  • Quantity of original liquid removed = initial quantity − final quantity.
  • For unequal replacements, multiply all remaining fractions: A × ∏(1 − q_i/V).
  • If the vessel initially contains only the original liquid, new liquid present = vessel volume − original liquid left.
  • For concentration, multiply the initial concentration by the remaining fraction of the original component.

Replacement Method FAQs

What is the mixture replacement formula?

If V is the vessel volume, q is replaced each time, A is the initial quantity of the original liquid, and n is the number of operations, then original liquid left = A[(V − q)/V]^n.

How much milk remains when 5 litres are replaced twice from a 20-litre vessel initially full of milk?

Milk left = 20[(20 − 5)/20]^2 = 20(3/4)^2 = 11.25 litres.

What fraction of the original liquid remains after replacing one-fifth of a mixture three times?

The remaining fraction in each operation is 4/5. After three operations, the fraction left is (4/5)^3 = 64/125.

How is the amount of new liquid found after repeated replacement?

If the vessel initially contains only the original liquid, subtract the original liquid left from the vessel volume. For a 20-litre vessel with 11.25 litres of original liquid left, the new liquid is 8.75 litres.

Can the same replacement formula be used when different quantities are removed?

Use the product form: final original quantity = A(1 − q₁/V)(1 − q₂/V) ... (1 − q_n/V). The quantities must be applied in sequence.

What happens if half the mixture is removed and replaced twice?

The original fraction left is (1/2)^2 = 1/4. Thus, one-fourth of the original liquid remains and three-fourths has been replaced by the new liquid.

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