Alligation: Formula, Rules and Solved Questions

Alligation is a method for finding the ratio in which two ingredients with different prices or concentrations must be mixed to obtain a required mean value. It uses the differences between the required mean and the two given values. The method applies to mixture price, concentration, purity and similar weighted-average questions.

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What Is Alligation?

Alligation is a shortcut method for finding the mixing ratio of two quantities having different values when their mixture must have a specified mean value. The required mean must lie between the two given values.

If the lower value is L, the higher value is H and the required mean is M, then the quantity ratio is lower-value quantity : higher-value quantity = (H − M) : (M − L). The same rule applies to prices, concentrations, efficiencies and other directly comparable quantities. For example, rice costing ₹30 per kg and ₹50 per kg gives a mixture costing ₹38 per kg in the ratio (50 − 38):(38 − 30) = 12:8 = 3:2.

Alligation Formula & Tricks

Important Formulas

Basic alligation formula
Quantity of lower value : Quantity of higher value = (Higher value − Mean value) : (Mean value − Lower value)

Use this when two values are mixed to obtain a specified mean value.

Mean value of a mixture
Mean value = (q₁v₁ + q₂v₂) / (q₁ + q₂)

Here, q₁ and q₂ are the quantities and v₁ and v₂ are their corresponding values.

Price-based alligation
Cheaper quantity : Dearer quantity = (Dearer price − Mean price) : (Mean price − Cheaper price)

The prices must use the same unit, such as rupees per kilogram.

Concentration-based alligation
Lower concentration quantity : Higher concentration quantity = (Higher concentration − Required concentration) : (Required concentration − Lower concentration)

Use percentages or fractions consistently for all concentrations.

Quick Tricks

Write the cross-differences

Place the lower value and higher value on opposite sides of the required mean. Subtract the mean from the higher value and the lower value from the mean. These cross-differences give the opposite quantities.

Example: For 20% and 50% solutions to obtain 30%, the ratio of 20% solution to 50% solution is (50 − 30):(30 − 20) = 20:10 = 2:1.
Check the mean range

The required mean must lie between the two given values. If it equals one given value, only that value is required; if it lies outside the range, ordinary two-value alligation is not possible.

Example: A mixture costing ₹45 per kg cannot be formed only from ingredients costing ₹30 and ₹40 per kg.
Find quantities from the ratio

After obtaining the ratio, add its parts and multiply each part by total quantity divided by total ratio parts.

Example: If the ratio is 3:2 and the total mixture is 25 kg, the quantities are 25 × 3/5 = 15 kg and 25 × 2/5 = 10 kg.

Alligation Concepts

Alligation Rule for Prices

For a cheaper and a dearer article, the quantity ratio required for a target mean price is the difference of the dearer price from the mean price to the difference of the mean price from the cheaper price.

If the cheaper price is C, the dearer price is D and the mean price is M, then cheaper quantity : dearer quantity = (D − M):(M − C). The mean price must be between C and D, and all prices must be expressed in the same unit.

Example: Tea at ₹120 per kg and ₹180 per kg is mixed to obtain tea at ₹150 per kg. The ratio is (180 − 150):(150 − 120) = 30:30 = 1:1.

Alligation for Concentration and Purity

The same alligation rule applies when two solutions or materials with different concentrations are mixed to obtain a required concentration.

For lower concentration L, higher concentration H and required concentration M, the quantity ratio is lower concentration : higher concentration = (H − M):(M − L). Percentages can be used directly because the common factor of 100 cancels.

Example: A 20% solution and a 50% solution are mixed to make a 30% solution. Their quantities must be in the ratio (50 − 30):(30 − 20) = 2:1.

Finding Actual Quantities from a Ratio

Once alligation gives a ratio, actual quantities are found by scaling the ratio to the stated total quantity.

If the ratio is a:b and the total quantity is T, then the quantities are Ta/(a + b) and Tb/(a + b). If one quantity is given, multiply both ratio parts by the factor obtained from that quantity.

Example: A 3:2 mixture has a total mass of 40 kg. The first component is 40 × 3/5 = 24 kg and the second is 40 × 2/5 = 16 kg.

Verification Using Weighted Average

The alligation ratio can be verified by calculating the weighted average of the two component values.

For quantities in the ratio a:b and values v₁ and v₂, the resulting mean is (av₁ + bv₂)/(a + b). This calculated mean must equal the required value.

Example: For prices ₹30 and ₹50 in the ratio 3:2, the mean price is (3 × 30 + 2 × 50)/5 = 190/5 = ₹38 per kg.

Alligation Video Lessons

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Alligation Rule: Cross Method

Learn how to apply the rule of alligation using the cross method to compare mixture values and determine the required ratio of ingredients.

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Practice Alligation Questions

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Alligation Quick Quiz

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Quick Revision Notes

Alligation Revision Points

Use these rules to revise the method and check calculations.

  • For lower value L, higher value H and mean M, the ratio is L-value quantity : H-value quantity = (H − M):(M − L).
  • The required mean must lie between the two component values.
  • Use the same units for all prices, concentrations or other values before applying alligation.
  • For a ratio a:b and total T, quantities are Ta/(a+b) and Tb/(a+b).
  • Verify the answer with the weighted-average formula: (q₁v₁ + q₂v₂)/(q₁ + q₂).
  • A mean closer to the lower value requires more of the lower-value component; a mean closer to the higher value requires more of the higher-value component.

Alligation FAQs

What is the alligation formula?

If L is the lower value, H is the higher value and M is the required mean, then lower-value quantity : higher-value quantity = (H − M):(M − L).

What ratio of ₹40 and ₹60 articles gives a mixture worth ₹45 per kg?

The ratio is (60 − 45):(45 − 40) = 15:5 = 3:1. Thus, ₹40 articles and ₹60 articles are mixed in the ratio 3:1.

How much of each solution is needed to make 60 litres of a 30% solution from 20% and 50% solutions?

The ratio is (50 − 30):(30 − 20) = 2:1. Therefore, use 60 × 2/3 = 40 litres of the 20% solution and 20 litres of the 50% solution.

Can alligation be used when the required mean is outside the two given values?

No. In ordinary two-component alligation, the required mean must be between the lower and higher values. A mean outside this range cannot be obtained by mixing only those two components.

Why are the differences placed opposite the quantities in alligation?

The quantity of one component is inversely related to its distance from the required mean. Therefore, the lower-value quantity receives the difference H − M, while the higher-value quantity receives M − L.

How do you verify an alligation ratio?

Use the weighted average. For a ratio a:b and values v₁ and v₂, calculate (av₁ + bv₂)/(a+b) and check whether it equals the required mean.

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