RRB NTPC UG Practice

Simplification Questions for RRB NTPC UG Exam

RRB NTPC UG Simplification Questions bring together the published questions available for this exam on PrepShots. Work through the set at your own pace, revise the underlying concepts when needed, and open any question to view its complete solution.

78Questions5Topics
FILTER

Practice by Topic

Start with all questions or focus on one topic.

QUESTION BANK

Simplification RRB NTPC UG Questions

Showing 1–20 of 78
Q1Which of the ratios given below is the greatest among them?
RRB NTPC (UG) CBT-I2026Fractions
Q2Simplify the following expression using the BODMAS rule: 3/4 + (5/6 × 9/10) - 2/3
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q3Simplify: { 12/33 ÷ 12/2 } ÷ ( 3/7 × 14/9 + 3/11 ) + 2/8 ÷ 31/25 of 25/8
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q4Simplify 10.5 - [6.5 - {3.3 - (3.2 - overline{2.2 - 1.8})}]
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q5Simplify: ((1.5 × 0.2))/0.3
RRB NTPC (UG) CBT-I2026Decimals
Q6Simplify: 30 + [{-9 × (26 - 11 + 6)}]
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q7Which of the following ratios is the greatest? a) 7 : 11 b) 9 : 14 c) 11 : 18 d) 13 : 21
RRB NTPC (UG) CBT-I2026Fractions
Q8Find the value of {1/0.01} × {[(5/8)+(0.25)] × (4/5)} .
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q9Simplify: 340/17 × 156/13 + 1484/28 - 14/10
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q10What should come in place of the question mark (?) in the following equation? (32 ÷ 0.8 × ?) - 72 = 720 ÷ (4 × 5 + 10)
RRB NTPC (UG) CBT-I2026Bodmas Rule
Simplification Questions for Railway Revise the concept, practise more PYQs and continue with timed questions for your exam.
Practice Free →
Q11A recipe requires 0.75 cups of sugar and 11/4cups of flour. What is the total amount (in cups) of ingredients used, expressed as a decimal?
RRB NTPC (UG) CBT-I2026Basic Operation
Q12Simplify: { 20/33 ÷ 20/7 } ÷ ( 3/5 × 10/9 + 2/11 ) + 7/4 ÷ 28/23 of 23/4
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q13Simplify: 92 + √42 - 7√16 - 7
RRB NTPC (UG) CBT-I2026Basic Operation
Q14Find the value of { 3.46 + 31/4 - 51/8 + 4.25 + 0.165 }
RRB NTPC (UG) CBT-I2026Basic Operation
Q15What is the simplified value of the following expression? {(33 + 52) × 23 - 43} ÷ (7 - 3)
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q16The value of {18 + [24 ÷ (3 of 2)] × 4} - 10 is equal to:
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q17Simplify: (19/18 ÷ 19/6) ÷ (5/18 × 16/15+4/6)+6/8 ÷ 24/25 of 25/8
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q18Simplify [8.16/2.4+(3.64 × 1.5)] to two decimal places.
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q19Find the value of (3+4/3 of 21/4 ÷ 22/5-21/4 of 31/5)
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q20Simplify: 1.2/0.3 - 2/5
RRB NTPC (UG) CBT-I2026Decimals
Loads the next 20 matching questions
LEARN

Revise Simplification Concepts

Need a quick concept refresh? Open the related PrepShots explainers before continuing practice.

SimplificationApproximationBasic CalculationBasic OperationsBODMAS RuleChange of Base FormulaDecimal to Fraction ConversionDecimal to Percentage
View all 26 topic explainers
DecimalsFraction to Decimal ConversionFraction to Percentage ConversionFractional IndicesFractionsIndicesLadder FractionLaws of IndicesLaws of LogarithmsLogarithmsNegative IndicesOperations on FractionsQuick MathsRationalization of SurdsSimplification of SurdsSurdsSurds and IndicesTypes of Surds
KEEP PRACTISINGSimplification Questions for Railway Exam

Continue with short revision, quizzes, PYQs and mock tests in PrepShots.

Open PrepShots →