Pythagorean Trigonometric Identities with Solved Examples
Pythagorean Trigonometric Identities are equations connecting the six trigonometric ratios. They are derived from the Pythagorean theorem and help find unknown ratios, simplify expressions and solve trigonometric questions. The three basic identities are sin²θ + cos²θ = 1, 1 + tan²θ = sec²θ and 1 + cot²θ = cosec²θ.
On this page
What Are Pythagorean Trigonometric Identities?
The fundamental identity is sin²θ + cos²θ = 1. Dividing it by cos²θ gives 1 + tan²θ = sec²θ, and dividing it by sin²θ gives 1 + cot²θ = cosec²θ. For example, if sin θ = 3/5 and θ is acute, then cos θ = 4/5 because (3/5)² + (4/5)² = 1.
Pythagorean Trigonometric Identities Video Lessons
Watch short topic-wise lessons for quick revision.
Pythagorean and Reciprocal Identities
Learn the fundamental Pythagorean and reciprocal identities in trigonometry, including their standard forms and how they relate the six trigonometric ratios.
Pythagorean Trigonometric Identities Formula & Tricks
Important Formulas
This identity follows by dividing the Pythagorean theorem by the square of the hypotenuse.
Divide sin²θ + cos²θ = 1 by cos²θ, where cos θ ≠ 0.
Divide sin²θ + cos²θ = 1 by sin²θ, where sin θ ≠ 0.
Rearrange the basic identities to find a missing squared ratio.
Quick Tricks
Use sin and cos together with sin²θ + cos²θ = 1. Use tan and sec together with sec²θ − tan²θ = 1. Use cot and cosec together with cosec²θ − cot²θ = 1.
For a 3-4-5 right triangle, the ratios are sin θ = 3/5, cos θ = 4/5, tan θ = 3/4, sec θ = 5/4, cosec θ = 5/3 and cot θ = 4/3, depending on which leg is opposite θ.
An identity determines a squared ratio, but not always its sign. Use the quadrant or the stated range of θ to choose the positive or negative value.
Pythagorean Trigonometric Identities Concepts
Fundamental Sine-Cosine Identity
In a right triangle, let the opposite, adjacent and hypotenuse sides be p, b and h. Since p² + b² = h², dividing by h² gives (p/h)² + (b/h)² = 1, which is sin²θ + cos²θ = 1. The notation sin²θ means (sin θ)².
Tangent and Secant Identity
Dividing sin²θ + cos²θ = 1 by cos²θ gives tan²θ + 1 = sec²θ because tan θ = sin θ/cos θ and sec θ = 1/cos θ. This form applies where cos θ is non-zero.
Cotangent and Cosecant Identity
Dividing sin²θ + cos²θ = 1 by sin²θ gives 1 + cot²θ = cosec²θ because cot θ = cos θ/sin θ and cosec θ = 1/sin θ. This form applies where sin θ is non-zero.
Finding Signs in Different Quadrants
For an acute angle, all six standard ratios are positive. In the second quadrant, sine and cosecant are positive; in the third quadrant, tangent and cotangent are positive; in the fourth quadrant, cosine and secant are positive. The remaining ratios in each quadrant are negative.
Pythagorean Trigonometric Identities Visual Guide
Use the diagram or chart below to understand the concept clearly.
3-4-5 Right Triangle for Pythagorean Identity
Learn more concepts on PrepShots
Start ₹1 Trial →Practice Pythagorean Trigonometric Identities Questions
Practise published questions related to this topic.
Want more practice questions?
Practice in App →Pythagorean Trigonometric Identities Quick Quiz
Attempt 5 questions and check your score instantly.
Keep practising
Practice more Pythagorean Trigonometric Identities questions in the PrepShots app and continue from your current topic.
Practice More Questions - Start ₹1 Trial →Quick Revision Notes
Pythagorean Trigonometric Identities Revision Points
Use these identities to calculate missing ratios and simplify trigonometric expressions.
- sin²θ + cos²θ = 1
- 1 + tan²θ = sec²θ
- 1 + cot²θ = cosec²θ
- sec²θ − tan²θ = 1 and cosec²θ − cot²θ = 1
- tan θ = sin θ/cos θ and cot θ = cos θ/sin θ
- sec θ = 1/cos θ and cosec θ = 1/sin θ
- Use the quadrant to select the sign after finding a squared ratio.
- The identities are valid only where the involved denominators are non-zero.
Pythagorean Trigonometric Identities FAQs
What is the main Pythagorean trigonometric identity?
The main identity is sin²θ + cos²θ = 1.
How is 1 + tan²θ = sec²θ obtained?
Divide sin²θ + cos²θ = 1 by cos²θ. This gives tan²θ + 1 = sec²θ, provided cos θ ≠ 0.
How is 1 + cot²θ = cosec²θ obtained?
Divide sin²θ + cos²θ = 1 by sin²θ. This gives 1 + cot²θ = cosec²θ, provided sin θ ≠ 0.
If sin θ = 5/13 and θ is acute, what is cos θ?
cos²θ = 1 − 25/169 = 144/169. Since θ is acute, cos θ = 12/13.
If tan θ = 3/4, what is sec θ for an acute angle?
sec²θ = 1 + (3/4)² = 25/16. Therefore sec θ = 5/4 for an acute angle.
What is the value of sec²θ − tan²θ?
The value is 1, because 1 + tan²θ = sec²θ.
