RRB NTPC UG Practice

Bodmas Rule Questions for RRB NTPC UG Exam

RRB NTPC UG Bodmas Rule Questions bring together the published questions available for this exam on PrepShots. Work through the set at your own pace, revise the underlying concepts when needed, and open any question to view its complete solution.

29Questions

Bodmas Rule RRB NTPC UG Questions

Showing 1–20 of 29
Q1Simplify the following expression using the BODMAS rule: 3/4 + (5/6 × 9/10) - 2/3
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q2Simplify: { 12/33 ÷ 12/2 } ÷ ( 3/7 × 14/9 + 3/11 ) + 2/8 ÷ 31/25 of 25/8
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q3Simplify 10.5 - [6.5 - {3.3 - (3.2 - overline{2.2 - 1.8})}]
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q4Simplify: 30 + [{-9 × (26 - 11 + 6)}]
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q5Find the value of {1/0.01} × {[(5/8)+(0.25)] × (4/5)} .
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q6Simplify: 340/17 × 156/13 + 1484/28 - 14/10
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q7What should come in place of the question mark (?) in the following equation? (32 ÷ 0.8 × ?) - 72 = 720 ÷ (4 × 5 + 10)
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q8Simplify: { 20/33 ÷ 20/7 } ÷ ( 3/5 × 10/9 + 2/11 ) + 7/4 ÷ 28/23 of 23/4
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q9What is the simplified value of the following expression? {(33 + 52) × 23 - 43} ÷ (7 - 3)
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q10The value of {18 + [24 ÷ (3 of 2)] × 4} - 10 is equal to:
RRB NTPC (UG) CBT-I2026Bodmas Rule
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Q11Simplify: (19/18 ÷ 19/6) ÷ (5/18 × 16/15+4/6)+6/8 ÷ 24/25 of 25/8
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q12Simplify [8.16/2.4+(3.64 × 1.5)] to two decimal places.
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q13Find the value of (3+4/3 of 21/4 ÷ 22/5-21/4 of 31/5)
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q14The simplified value of ((12/24))/((12/6)) ÷ (2/9 × 18/6 + 4/8) + 6/9 ÷ 28/11 of 11/9 is
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q15Simplify: ((10/18))/((10/9)) ÷ (4/9 × 18/12 + 5/6) + 9/9 ÷ 27/15 of 15/9
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q16Simplify: ((16/21))/((16/4)) ÷ (4/5 × 10/12 + 4/7) + 4/8 ÷ 26/14 of 14/8
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q17The value of (2+3/2)² - [4-(6/3)²] ÷ 1/2 is
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q18Simplify: 156 ÷ [12 + {7 × (15 - 9) - 28}]
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q19Simplify: ((13/21))/((13/10)) ÷ (5/9 × 18/15+5/7)+10/6 ÷ 29/15 of 15/6
RRB NTPC (UG) CBT-I2026Bodmas Rule
Q20Simplify {(13/33) ÷ (13/7)} ÷ (2/8 × 16/6+5/11)+7/3 ÷ 37/20 of 20/3
RRB NTPC (UG) CBT-I2026Bodmas Rule
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