Multiplication Theorem of Probability: Formula, Rules and Examples

Multiplication Theorem of Probability gives the probability of the simultaneous occurrence of two or more events. It expresses a joint probability using the probability of one event and the conditional probability of the next event. This page covers its formulas, independent and dependent events, sequential applications, solved examples and common probability problems.

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What is the Multiplication Theorem of Probability?

The Multiplication Theorem of Probability states that the probability of both events A and B occurring is P(A ∩ B) = P(A)P(B|A).

Here, P(B|A) is the probability of B when A has already occurred. The equivalent form is P(A ∩ B) = P(B)P(A|B). For several events, P(A₁ ∩ A₂ ∩ A₃) = P(A₁)P(A₂|A₁)P(A₃|A₁ ∩ A₂).

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Independent Events and Multiplication Theorem

Learn how to identify independent events and apply the multiplication theorem to calculate the probability of their joint occurrence.

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Multiplication Theorem of Probability Formula & Tricks

Important Formulas

Two-event multiplication formula
P(A ∩ B) = P(A) × P(B|A)

The joint probability of A and B equals the probability of A multiplied by the conditional probability of B after A occurs.

Reverse form
P(A ∩ B) = P(B) × P(A|B)

The same joint probability can be calculated by taking B first and then finding the conditional probability of A given B.

Independent events
P(A ∩ B) = P(A) × P(B)

If A and B are independent, the occurrence of one does not change the probability of the other.

Three-event form
P(A ∩ B ∩ C) = P(A) × P(B|A) × P(C|A ∩ B)

For successive events, each factor is the probability of the next event given that all preceding events have occurred.

Quick Tricks

Use the order that gives simpler conditional probability

Since P(A ∩ B) can be written in either order, choose P(A)P(B|A) or P(B)P(A|B) according to the easier conditional probability.

Example: If P(A) = 1/2 and P(B|A) = 3/5, then P(A ∩ B) = 1/2 × 3/5 = 3/10.
Update the denominator after selection without replacement

When an object is selected and not replaced, the total number of remaining objects decreases before calculating the next conditional probability.

Example: From 5 red and 3 blue balls, the probability of drawing two red balls without replacement is 5/8 × 4/7 = 5/14.
Do not remove the conditional term for dependent events

Use P(A)P(B) only for independent events. If the first event changes the second probability, use P(A)P(B|A).

Example: Two aces from a deck without replacement have probability 4/52 × 3/51 = 1/221, not (4/52)².

Multiplication Theorem of Probability Concepts

Conditional probability form

For two events, the multiplication theorem is P(A ∩ B) = P(A)P(B|A).

The intersection A ∩ B means that both A and B occur. The conditional factor P(B|A) is calculated after assuming that A has occurred. If P(A) is non-zero, then P(B|A) = P(A ∩ B)/P(A).

Example: If P(A) = 2/5 and P(B|A) = 3/4, then P(A ∩ B) = 2/5 × 3/4 = 3/10.

Successive dependent events

For events occurring in sequence, multiply the probability at each stage using the updated conditions.

For three events, P(A ∩ B ∩ C) = P(A)P(B|A)P(C|A ∩ B). In sampling without replacement, the numerator and denominator change after every selection.

Example: A bag has 4 white and 2 black balls. The probability of drawing three white balls without replacement is 4/6 × 3/5 × 2/4 = 1/5.

Independent events

For independent events, P(B|A) = P(B), so the theorem becomes P(A ∩ B) = P(A)P(B).

Events are independent when the occurrence of one event does not alter the probability of the other. Repeated tosses of a fair coin are independent, provided the tosses do not influence one another.

Example: The probability of getting a head on two successive fair coin tosses is 1/2 × 1/2 = 1/4.

Mutually exclusive versus independent events

Mutually exclusive events cannot occur together, whereas independent events do not change each other's probabilities.

If A and B are mutually exclusive, then P(A ∩ B) = 0. If both events have positive probability, mutually exclusive events cannot be independent because P(A)P(B) is then positive.

Example: On one die roll, getting 2 and getting 5 are mutually exclusive, so their joint probability is 0. They are not independent.

Tree-based multiplication of probabilities

In a probability tree, multiply the probabilities along one path to obtain that path's joint probability.

For alternative paths, calculate each path probability separately and add the required path probabilities. Every branch probability must be conditional on the outcomes already shown on that path.

Example: If a first-stage path has probability 2/5 and its next branch has probability 3/7, the path probability is 2/5 × 3/7 = 6/35.

Multiplication Theorem of Probability Data Table

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Comparison of event relationships

The multiplication rule changes according to whether the events affect one another.

Event relationship Condition Joint probability
General events B may depend on A P(A ∩ B) = P(A)P(B|A)
Independent events P(B|A) = P(B) P(A ∩ B) = P(A)P(B)
Mutually exclusive events A and B cannot occur together P(A ∩ B) = 0

Note: Events with positive probabilities cannot be both mutually exclusive and independent.

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Quick Revision Notes

Multiplication Theorem of Probability: Revision Points

Use these rules to revise joint probabilities and sequential event calculations.

  • P(A ∩ B) = P(A)P(B|A) = P(B)P(A|B).
  • For independent events, P(A ∩ B) = P(A)P(B).
  • For three events, multiply the first probability by each successive conditional probability.
  • Without replacement, update the total and favourable outcomes after every selection.
  • Mutually exclusive events have joint probability zero.
  • In a probability tree, multiply along a path and add probabilities of alternative required paths.

Multiplication Theorem of Probability FAQs

What is the multiplication theorem of probability formula?

The formula is P(A ∩ B) = P(A)P(B|A) = P(B)P(A|B), where P(B|A) is the probability of B given A.

How is the formula used for independent events?

For independent events, P(B|A) = P(B). Therefore, P(A ∩ B) = P(A)P(B).

What is the probability of drawing two aces consecutively without replacement?

It is 4/52 × 3/51 = 1/221, because there are 4 aces initially and 3 aces after one ace is drawn.

How do you calculate the probability of three successive events?

Use P(A ∩ B ∩ C) = P(A)P(B|A)P(C|A ∩ B). Each later factor includes the outcomes of the earlier events.

Can mutually exclusive events be independent?

Only in the special case where at least one event has probability zero. If both probabilities are positive, mutually exclusive events are not independent.

What is the difference between with-replacement and without-replacement probability?

With replacement, the composition and probabilities remain unchanged. Without replacement, the total and favourable counts change after each selection.

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