SSC CGL Practice

Bodmas Rule Questions for SSC CGL Exam

SSC CGL Bodmas Rule Questions bring together the published questions available for this exam on PrepShots. Work through the set at your own pace, revise the underlying concepts when needed, and open any question to view its complete solution.

32Questions

Bodmas Rule SSC CGL Questions

Showing 1–20 of 32
Q1The value of ({36 ÷ 42 of 6 × 7 + 24 × 6 ÷ 18 + 3 ÷ ( {2 - 6} ) - ( {4 + 3 × 2} ) ÷ 8})/({21 ÷ 3 of 7}) is:
SSC CGL2020Bodmas Rule
Q2The value of ( {18 ÷ 2 of1/4} ) × ( {2/3 ÷ 3/4 × 5/8} ) ÷ ( {2/3 ÷ 3/4of3/4} ) is:
SSC CGL2020Bodmas Rule
Q3If '+' means '-', '-' means '+', ' × ' means ' ÷ ' and ' ÷ ' means ' × ', then the value of ({42 - 12 × 3 + 8 ÷ 2 + 15})/({8 × 2 - 4 + 9 ÷ 3}) is:
SSC CGL2020Bodmas Rule
Q4What is the value of 9991 × 10009?
SSC CGL2017Bodmas Rule
Q593/4 ÷ [ {21/6 ÷ { {41/3 - ( {21/2 + 3/4} )} }} ] is equal to:
SSC CGL2019Bodmas Rule
Q6The value of 15.2 + 5.8 ÷ 2.9 × 2 - 3.5 × 2 ÷ 0.5 is equal to:
SSC CGL2019Bodmas Rule
Q721.6 ÷ 3.6 × 2 + 0.25 × 16 ÷ 4 - 6 is equal to∶
SSC CGL2019Bodmas Rule
Q8Find the value of 108 ÷ 36 × 4 + 2.5 × 4 ÷ 0.5 - 10
SSC CGL2019Bodmas Rule
Q9The value of (26 - 13 × 2) ÷ 2 + 1 is:
SSC CGL2020Bodmas Rule
Q10Solve the following expression. 11 + 11 × 11 - 11 ÷ 11
SSC CGL2020Bodmas Rule
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Q11If 'A' stands for 'subtraction', 'B' stands for 'multiplication', 'C' stands for 'addition' and 'D' stands for 'division', then what is the value of the following expression? 32 B 4 A 12 B (35 A 24) C 52 D 4
SSC CGL2020Bodmas Rule
Q12The value of 1800 ÷ 20 × {(12 - 6) + (24 - 12)} is:
SSC CGL2020Bodmas Rule
Q13Solve the following expression. 5.6 - {2 + 0.6 of (2.1 - 2.6 × 1.12)}
SSC CGL2020Bodmas Rule
Q14The value of 11/8 ÷ ( {41/4 ÷ 3/5of 81/2} ) - 2/5 × 11/3 ÷ 4/5of 12/3 + ({11})/({20}) is:
SSC CGL2020Bodmas Rule
Q15The value of 3 - (9 - 3 × 8 ÷ 2) is:
SSC CGL2020Bodmas Rule
Q16The value of 6 - 6 ÷ 6 × 6 + (6 ÷ 6 of 6) × 6 - ( {32/3 ÷ ({11})/3{{of}}2/3 ÷ 5} ) is:
SSC CGL2019Bodmas Rule
Q17The value of 71/2{{}} × {{}}( {31/5{{}} ÷ {{}}51/3{{of }}41/2} ){{}} + {{}}[ {11 - ( {5/8{{}} + {{}}3 - 11/4} )} ]{{}} ÷ {{}}53/4 - 5{{ }} ÷ {{ }}5{{}} × {{}}5{{ of }}5{{ }} ÷ {{ }}25 is:
SSC CGL2019Bodmas Rule
Q18The value of ({[ {54 - ( {5 ÷ 2} ) × 8} ] + 13})/({48 - 4 ÷ 3 × 8 - 2})
SSC CGL2020Bodmas Rule
Q19Solve the following.4/3 ÷ 1/6 × 2 - 1 = ?
SSC CGL2020Bodmas Rule
Q20If '+' means '-', '-' means '+', ' × ' means ' ÷ ' and ' ÷ ' means ' × ' then the value of ({[ {( {30 × 5} ) + ( {84 × 6} )} ] ÷ 5})/({[ {2/3 ÷ 18} ] - [ {4 ÷ 2} ]})
SSC CGL2020Bodmas Rule
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