How to Calculate New Average After Adding a Member?
Average After Adding a Member problems compare the original total with the total after one new value is included. If a group has n members and average a, its total is na. After adding a member with value x, the new average is found by dividing na + x by n + 1.
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What Is the Average After Adding a Member?
The average after adding a member is calculated as (na + x)/(n + 1). If the new average b is known, the added member's value is x = (n + 1)b - na. The new average increases when x is greater than the old average and decreases when x is less than the old average.
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Average: Adding or Removing a Member
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Average After Adding a Member Formula & Tricks
Important Formulas
Here, n is the original number of members, a is the original average, and x is the value of the added member.
Here, b is the new average after adding the member.
If the average changes by d, where d = new average - old average, the added member's value is a + (n + 1)d.
The increase or decrease in average equals the difference between the added value and old average divided by the new number of members.
Quick Tricks
First find the original total as number of members multiplied by the old average. Add the new member's value, then divide by the new count.
If the added value is above the old average, the average rises; if it is below the old average, the average falls. The change is (x − a)/(n + 1).
Average After Adding a Member Concepts
Finding the New Average When the Added Value Is Known
For n members with average a, the old total is na. After adding value x, the total becomes na + x and the count becomes n + 1. Therefore, the new average is (na + x)/(n + 1).
Finding the Added Member When the New Average Is Known
If the old average is a for n members and the new average is b for n + 1 members, then old total = na and new total = (n + 1)b. Hence, added value = (n + 1)b − na.
Effect of the Added Member on the Average
The change is d = (x − a)/(n + 1). A value equal to the old average causes no change. A value greater than the old average increases the average, while a smaller value decreases it.
Finding the Original Average or Group Size
If the added value x, old average a and new average b are known, the original count satisfies na + x = (n + 1)b, so n(a − b) = b − x and n = (b − x)/(a − b), when a is not equal to b.
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Average After Adding a Member: Revision Points
Use totals and the new count to solve every one-member addition problem.
- Original total = original number × original average.
- New total after addition = old total + value of added member.
- New average = (na + x)/(n + 1).
- Added value = (n + 1)b − na.
- Change in average = (x − a)/(n + 1).
- The average remains unchanged only when the added value equals the old average.
Average After Adding a Member FAQs
What is the average after adding one member?
If n members have average a and the added member has value x, the new average is (na + x)/(n + 1).
How do you find the added member's value when the average changes?
Use x = a + (n + 1)d, where d is the change in average. For example, if a = 20, n = 7 and the average rises by 2, x = 20 + 8 × 2 = 36.
A group of 12 has average 15. If a member with value 28 joins, what is the new average?
Old total = 12 × 15 = 180. New average = (180 + 28)/13 = 208/13 = 16.
The average of 8 numbers is 21 and becomes 22 after one number is added. What is the added number?
Added number = 9 × 22 − 8 × 21 = 198 − 168 = 30.
When does adding a member leave the average unchanged?
The average remains unchanged when the added member's value equals the old average. For example, adding 18 to a group whose average is 18 does not change the average.
How is the original group size found if the added value and both averages are known?
Use n = (b − x)/(a − b), where a is the old average, b is the new average and x is the added value. If a = 26, b = 25 and x = 20, n = (25 − 20)/(26 − 25) = 5.
