How to Find the Average of Consecutive Numbers?

Average of Consecutive Numbers is found by using the middle term for an odd number of equally spaced terms, or the midpoint of the two middle terms for an even number of terms. This page covers the average of consecutive integers, consecutive even and odd numbers, standard formulas, and short methods for solving aptitude questions.

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What Is the Average of Consecutive Numbers?

The average of consecutive numbers is the arithmetic mean of numbers arranged with an equal difference between successive terms. For consecutive integers, the difference is 1; for consecutive even or odd numbers, the difference is 2.

If the first term is a and the last term is l, the average is (a + l) ÷ 2. For an odd number of consecutive terms, the average is the middle term. For an even number of terms, it lies halfway between the two middle terms. For example, the average of 12, 13, 14, 15 and 16 is 14.

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Average of AP and Consecutive Numbers

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Average of Consecutive Numbers Formula & Tricks

Important Formulas

Basic average formula
Average = Sum of terms ÷ Number of terms

Add all the terms and divide the sum by their count.

First and last term formula
Average = (First term + Last term) ÷ 2

This applies to any equally spaced sequence, including consecutive integers, even numbers and odd numbers.

n consecutive integers
Average = a + (n − 1) ÷ 2

Here, a is the first integer and n is the number of terms. The last term is a + n − 1.

n equally spaced terms
Average = a + (n − 1)d ÷ 2

Here, a is the first term and d is the common difference. For consecutive even or odd numbers, d = 2.

Sum of terms
Sum = Number of terms × Average

If the average and number of terms are known, their product gives the total sum.

Quick Tricks

Use the middle term

For an odd number of equally spaced terms, select the middle term directly instead of adding every number.

Example: The average of 21, 22, 23, 24 and 25 is the middle term, 23.
Pair the first and last terms

In an equally spaced sequence, the sum of the first and last terms equals the sum of the second and second-last terms. Therefore, the average is the midpoint of the first and last terms.

Example: For 8, 11, 14, 17 and 20, the average is (8 + 20) ÷ 2 = 14.
Shift the centre when terms are removed

If equal numbers of terms are removed from both ends, the average remains unchanged. If terms are removed only from one side, recalculate using the new first and last terms.

Example: The average of 10, 11, 12, 13 and 14 is 12. Removing 10 and 14 leaves 11, 12 and 13, whose average is also 12.

Average of Consecutive Numbers Concepts

Average of Consecutive Integers

For consecutive integers, the average equals the mean of the first and last integers.

If the terms are a, a + 1, a + 2, ..., a + n − 1, then average = [a + (a + n − 1)] ÷ 2 = a + (n − 1) ÷ 2. When n is odd, this value is an integer and is the middle term. When n is even, it may be a fraction or end in .5.

Example: The average of 15, 16, 17, 18, 19 and 20 is (15 + 20) ÷ 2 = 17.5.

Average of Consecutive Even Numbers

For consecutive even numbers, the common difference is 2, so the average is the mean of the first and last even numbers.

For n terms beginning with a, the sequence is a, a + 2, a + 4, ..., a + 2(n − 1). Its average is [a + a + 2(n − 1)] ÷ 2 = a + n − 1.

Example: The average of 18, 20, 22, 24 and 26 is (18 + 26) ÷ 2 = 22.

Average of Consecutive Odd Numbers

For consecutive odd numbers, the common difference is also 2, so the average is the midpoint of the first and last odd numbers.

For n terms beginning with a, the sequence is a, a + 2, a + 4, ..., a + 2(n − 1). The average is a + n − 1. With an odd number of terms, the average is the central odd number.

Example: The average of nine consecutive odd numbers from 13 to 29 is (13 + 29) ÷ 2 = 21.

Finding the Number of Terms

For consecutive integers, the number of terms is Last term − First term + 1.

For equally spaced terms with common difference d, the number of terms is n = [(Last term − First term) ÷ d] + 1. For consecutive even or odd numbers, use d = 2.

Example: The number of even numbers from 14 to thirty? Need correct string. Let's make: from 14 to thirty? Use 30: n = (30 − 14) ÷ 2 + 1 = 9.

Finding Consecutive Numbers from Their Average

If the number of consecutive terms and their average are known, the average gives the centre of the sequence.

For an odd number of consecutive integers, the average is the middle integer. For n terms with common difference d, the first term is Average − [(n − 1)d ÷ 2], and the last term is Average + [(n − 1)d ÷ 2].

Example: Five consecutive integers have average 32. The middle term is 32, so the numbers are 30, 31, 32, 33 and 34.

Average of Consecutive Numbers Data Table

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Examples by Number Type

The first and last terms determine the average of each equally spaced sequence.

Number type Terms Calculation Average
Consecutive integers 7, 8, 9, 10, 11 (7 + 11) ÷ 2 9
Consecutive even numbers 12, 14, 16, 18 (12 + 18) ÷ 2 15
Consecutive odd numbers 17, 19, 21, 23, 25 (17 + 25) ÷ 2 21

Note: The common difference is 1 for consecutive integers and 2 for consecutive even or odd numbers.

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Quick Revision Notes

Average of Consecutive Numbers: Revision Points

Use these formulas and rules for quick revision.

  • Average of equally spaced terms = (First term + Last term) ÷ 2.
  • For n consecutive integers beginning with a, average = a + (n − 1) ÷ 2.
  • For n consecutive even or odd numbers beginning with a, average = a + n − 1.
  • Number of consecutive integers = Last term − First term + 1.
  • Number of equally spaced terms = [(Last term − First term) ÷ Common difference] + 1.
  • For an odd number of terms, the average is the middle term.
  • For an even number of terms, the average is halfway between the two middle terms.
  • Sum of terms = Number of terms × Average.

Average of Consecutive Numbers FAQs

What is the average of the first 10 natural numbers?

The numbers are 1 to 10. Average = (1 + 10) ÷ 2 = 5.5.

What is the average of 20 consecutive integers starting from 11?

The last integer is 30. Average = (11 + 30) ÷ 2 = 20.5.

What is the average of the first eight even numbers?

The first eight positive even numbers are 2 to 16. Average = (2 + 16) ÷ 2 = 9.

Can the average of consecutive integers be a decimal?

Yes. An even number of consecutive integers has an average ending in .5, such as the average of 4, 5, 6 and 7, which is 5.5.

What is the average of 7 consecutive odd numbers with middle term 25?

The average is the middle term, so it is 25. The numbers are 19, 21, 23, 25, 27, 29 and 31.

How many consecutive odd numbers are there from nine to 31?

Using n = [(31 − 9) ÷ 2] + 1, n = 11 + 1 = 12. However, 9 and 31 are both odd and the sequence contains 12 terms: 9, 11, ..., 31.

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