Cube of Difference Identity with Algebraic Examples
Cube of Difference Identity expands the cube of a binomial in the form (a − b)³. The expansion contains four terms with coefficients 1, 3, 3, 1 and alternating signs. This page explains the formula, sign order, direct substitution, algebraic expansion and common cube of difference identity problems.
On this page
What Is the Cube of Difference Identity?
The terms are formed from a³, a²b, ab² and b³. Their coefficients follow 1, 3, 3, 1, while the signs alternate as positive, negative, positive, negative. For example, (x − 2)³ = x³ − 6x² + 12x − 8.
Cube of Difference Identity Video Lessons
Watch short topic-wise lessons for quick revision.
Cube Identities: A Plus or Minus B
Learn the cube identities for (A+B)³ and (A−B)³, along with the factorisations of A³+B³ and A³−B³ for solving algebraic expressions.
Cube of Difference Identity Formula & Tricks
Important Formulas
Use this identity when a binomial is raised to the third power and its terms are separated by a minus sign.
The expanded expression can be recognised and written as a perfect cube.
This form is obtained by grouping the first and last cube terms in the standard expansion.
Quick Tricks
Write the powers of the first term from 3 to 0 and the powers of the second term from 0 to 3. Multiply the middle terms by 3, and use the sign pattern +, −, +, −.
For an algebraic expansion, assign small values to the variables and compare both sides. This helps detect sign or coefficient errors.
Cube of Difference Identity Concepts
Direct Application of the Identity
Keep the first quantity as a and the subtracted quantity as b. Calculate the four terms separately before combining them. This avoids errors in the middle terms.
Expansion of Algebraic Binomials
The general expansion is x³ − 3kx² + 3k²x − k³. If the second term contains a variable, multiply the powers carefully.
Finding a Perfect Cube from Its Expansion
The first and last terms identify a and b through their cubes. The two middle terms must have coefficients and signs consistent with 3a²b and 3ab².
Using the Identity for Numerical Calculation
Choose a and b so that a − b equals the required number and the powers of a and b are easy to calculate.
Cube of Difference Identity Data Table
Use the structured data below while following the explanation and examples.
Term and Sign Pattern
The four terms in the cube of difference identity follow descending powers of a and ascending powers of b.
| Term position | Term | Sign | Coefficient |
|---|---|---|---|
| 1 | a³ | + | 1 |
| 2 | 3a²b | − | 3 |
| 3 | 3ab² | + | 3 |
| 4 | b³ | − | 1 |
Note: The signs are +, −, +, − when the expression is (a − b)³.
Learn more concepts on PrepShots
Start ₹1 Trial →Practice Cube of Difference Identity Questions
Practise published questions related to this topic.
Want more practice questions?
Practice in App →Cube of Difference Identity Quick Quiz
Attempt 5 questions and check your score instantly.
Keep practising
Practice more Cube of Difference Identity questions in the PrepShots app and continue from your current topic.
Practice More Questions - Start ₹1 Trial →Quick Revision Notes
Cube of Difference Identity Revision Points
Recall the formula, coefficient pattern and conditions for identifying a perfect cube.
- (a − b)³ = a³ − 3a²b + 3ab² − b³.
- The coefficients are 1, 3, 3, 1.
- The signs alternate as +, −, +, −.
- The powers of a decrease from 3 to 0, while the powers of b increase from 0 to 3.
- For (x − k)³, the expansion is x³ − 3kx² + 3k²x − k³.
- Do not confuse (a − b)³ with a³ − b³; the latter omits the two middle terms.
Cube of Difference Identity FAQs
What is the cube of difference identity formula?
The formula is (a − b)³ = a³ − 3a²b + 3ab² − b³.
How do you expand (x − 5)³?
(x − 5)³ = x³ − 3(x²)(5) + 3(x)(25) − 125 = x³ − 15x² + 75x − 125.
What is the value of (10 − 3)³ using the identity?
(10 − 3)³ = 10³ − 3(10²)(3) + 3(10)(3²) − 3³ = 343.
How is (a − b)³ different from a³ − b³?
(a − b)³ = a³ − 3a²b + 3ab² − b³ contains two middle terms. The expression a³ − b³ has only the first and last cube terms.
How can x³ − 12x² + 48x − 64 be written as a cube?
Compare it with a³ − 3a²b + 3ab² − b³. Here a = x and b = 4, so the expression is (x − 4)³.
What is the expansion of (2a − b)³?
(2a − b)³ = 8a³ − 12a²b + 6ab² − b³.
