How to Solve Two-Set Venn Diagram Problems?
Two-Set Venn Diagram Problems represent relationships between two groups using overlapping circles. This page explains union, intersection, elements in only one set, neither set and the universal set. It also gives formulas, calculation methods, shortcuts and solved numerical examples for quantitative aptitude questions.
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What Are Two-Set Venn Diagram Problems?
The complete region covered by either circle represents A ∪ B. If the universal set contains N elements, the number outside both circles is N − n(A ∪ B). For example, if n(A) = 32, n(B) = 25 and n(A ∩ B) = 9, then n(A ∪ B) = 32 + 25 − 9 = 48.
Two-Set Venn Diagram Problems Video Lessons
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Venn Diagram Two-Set Problems
Learn to solve two-set Venn diagram survey problems using set relationships, intersections, unions, and the inclusion-exclusion principle.
Two-Set Venn Diagram Problems Formula & Tricks
Important Formulas
Add the sizes of A and B, then subtract the common elements because they were counted twice.
Subtract the union from the total number of elements in the universal set.
This counts elements in A only and B only, excluding the overlap.
Remove the common region from each set to find its exclusive part.
At least one means belonging to A, B or both.
Quick Tricks
When separate-set totals and the common total are given, place the intersection first. Then subtract it from each set to obtain A only and B only.
For questions asking for neither, first calculate the union and subtract it from the universal-set total.
The intersection cannot exceed the smaller set. Therefore, n(A ∩ B) ≤ min[n(A), n(B)]. Also, the union cannot exceed the universal-set total.
Two-Set Venn Diagram Problems Concepts
Intersection and Common Elements
If n(A ∩ B) = x, then x elements are placed in the overlapping part of the two circles. The intersection is included in both n(A) and n(B), so it must be subtracted once while finding the union.
Union and At Least One Set
Use n(A ∪ B) = n(A) + n(B) − n(A ∩ B). The subtraction prevents the common elements from being counted twice.
Only A, Only B and Exactly One
The regions are A only = n(A) − n(A ∩ B) and B only = n(B) − n(A ∩ B). Exactly one set is the sum of these two regions.
Neither Set and the Universal Set
First calculate the union, then use neither = N − n(A ∪ B), where N is the total number of elements. If every element belongs to at least one set, the neither region is zero.
Two-Set Venn Diagram Problems Visual Guide
Use the diagram or chart below to understand the concept clearly.
Two-set Venn diagram with four regions
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Two-Set Venn Diagram Revision Points
Use the set totals and overlap to calculate each region of a two-set Venn diagram.
- n(A ∪ B) = n(A) + n(B) − n(A ∩ B).
- A only = n(A) − n(A ∩ B).
- B only = n(B) − n(A ∩ B).
- Exactly one = n(A) + n(B) − 2n(A ∩ B).
- Neither = N − n(A ∪ B).
- At least one means the union; both means the intersection.
- The intersection cannot be greater than either individual set.
- The total of A only, intersection, B only and neither equals the universal-set total.
Two-Set Venn Diagram Problems FAQs
What is the formula for the union of two sets?
The formula is n(A ∪ B) = n(A) + n(B) − n(A ∩ B). The intersection is subtracted because common elements are counted in both set totals.
How do you find the number of people in neither set?
Use neither = N − n(A ∪ B). For example, if N = 90 and the union is 68, then 22 people belong to neither set.
How do you calculate exactly one of two sets?
Exactly one = n(A) + n(B) − 2n(A ∩ B). If the set sizes are 26 and 19 and the intersection is 6, exactly one is 26 + 19 − 12 = 33.
What is the difference between at least one and exactly one?
At least one includes the intersection, so it equals A ∪ B. Exactly one excludes the intersection and includes only A and only B.
If 45 people are in A, 32 are in B and 14 are in both, how many are in at least one set?
n(A ∪ B) = 45 + 32 − 14 = 63. Therefore, 63 people are in at least one set.
Can the intersection of two sets be greater than one of the sets?
No. The intersection must satisfy n(A ∩ B) ≤ n(A) and n(A ∩ B) ≤ n(B).
