Geometry Based Permutation and Combination with Examples

Geometry Based Permutation and Combination applies selection and arrangement formulas to points, lines, polygons, diagonals, chords and geometric figures. The main methods use combinations because geometric objects are usually selected without order. Special care is needed for collinear points, repeated intersections and circular arrangements.

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What is Geometry Based Permutation and Combination?

Geometry based permutation and combination counts geometric figures or arrangements formed by selecting points, lines, vertices or chords. Combinations are used when the order of selected elements does not change the figure.

For example, any three non-collinear points determine one triangle, so n points with no three collinear points form C(n, 3) triangles. Similarly, joining every pair of n points gives C(n, 2) line segments or chords. If some points are collinear, selections that do not form the required figure must be subtracted.

Geometry Based Permutation and Combination Video Lessons

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Geometry-Based Permutation and Combination

Learn how to solve permutation and combination problems involving geometric arrangements, using appropriate counting methods to determine possible configurations.

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Geometry Based Permutation and Combination Formula & Tricks

Important Formulas

Selection of r points
C(n, r) = n! / [r!(n-r)!]

Use this when r points, vertices or objects are selected from n objects and their order does not matter.

Triangles from polygon vertices
Number of triangles = C(n, 3) = n(n-1)(n-2)/6

This applies when all n points are vertices and no three selected points are collinear.

Diagonals of an n-sided polygon
Number of diagonals = C(n, 2) - n = n(n-3)/2

Every pair of vertices gives a segment, but the n sides are not diagonals.

Line segments joining n points
Number of segments = C(n, 2) = n(n-1)/2

Each segment is determined by choosing two distinct endpoints.

Regions formed by all chords of n points on a circle
Maximum regions = 1 + C(n, 2) + C(n, 4)

This maximum applies when no three chords meet at an interior point and every pair of chords with distinct endpoints intersects inside the circle.

Quick Tricks

Count vertices first for triangles

A triangle is determined by selecting three vertices. Do not arrange the three vertices, because different orders represent the same triangle.

Example: A hexagon has C(6, 3) = 20 triangles formed by its vertices.
Subtract sides when counting diagonals

First count all pairs of polygon vertices using C(n, 2). Remove the n adjacent pairs that form sides.

Example: For an octagon, diagonals = C(8, 2) - 8 = 28 - 8 = 20.
Correct for collinear selections

If k points lie on one straight line, C(k, 3) selections from that line do not form triangles. Subtract these invalid selections from the total.

Example: If 8 points include 4 collinear points and no other three are collinear, triangles = C(8, 3) - C(4, 3) = 56 - 4 = 52.
Use the chord-region formula only for maximum regions

The expression 1 + C(n, 2) + C(n, 4) assumes that no three chords are concurrent inside the circle. If three or more chords meet at one interior point, the actual number of regions is smaller.

Example: For 5 points on a circle in general position, maximum regions = 1 + C(5, 2) + C(5, 4) = 1 + 10 + 5 = 16.

Geometry Based Permutation and Combination Concepts

Triangles from Points or Polygon Vertices

Three non-collinear points determine exactly one triangle, so the number of triangles from n such points is C(n, 3).

The selection is a combination because the order of the three chosen points does not matter. If points lie on the same straight line, their selection is invalid for triangle formation and must be removed.

Example: From 7 points with no three collinear, the number of triangles is C(7, 3) = 35.

Effect of Collinear Points

Collinear triples must be subtracted because they form a straight line rather than a triangle.

If n total points contain groups of k1, k2, ... collinear points, and no invalid triple is counted twice, then triangles = C(n, 3) - C(k1, 3) - C(k2, 3) - .... For overlapping or more complicated configurations, count each invalid selection carefully.

Example: Among 9 points, 5 are collinear and no other three are collinear. The number of triangles is C(9, 3) - C(5, 3) = 84 - 10 = 74.

Diagonals and Segments of a Polygon

An n-sided polygon has C(n, 2) total vertex pairs and n diagonals are obtained after excluding its sides.

Every pair of vertices determines one segment. Adjacent vertex pairs determine the n sides, while the remaining pairs determine diagonals. Therefore, diagonals = C(n, 2) - n = n(n-3)/2.

Example: A decagon has 10(10-3)/2 = 35 diagonals and C(10, 2) = 45 total segments joining pairs of vertices.

Chords and Regions in a Circle

Joining every pair of n points on a circle gives C(n, 2) chords, while the maximum number of regions is 1 + C(n, 2) + C(n, 4).

The region formula counts the initial region, the chords themselves, and the interior intersections created by choosing four distinct circle points. It is valid only when no three chords intersect at one interior point.

Example: With 6 points on a circle, chords = C(6, 2) = 15. Maximum regions = 1 + C(6, 2) + C(6, 4) = 1 + 15 + 15 = 31.

Selecting Sides or Diagonals

Selecting r sides or diagonals from a set of m distinct segments is counted by C(m, r), unless an additional geometric condition is imposed.

If the question only asks for a group of segments, use combinations. If the selected segments must be non-adjacent, intersecting, parallel or form a particular figure, first identify and exclude selections that violate that condition.

Example: Choosing 3 diagonals from the 20 diagonals of an octagon gives C(20, 3) = 1,140 selections before applying any extra condition.

Geometry Based Permutation and Combination Visual Guide & Data

Use the table and chart below to understand the data better.

Common Geometry-Based Counting Results

Formulas for selecting points and counting polygon segments, diagonals and circle regions.

Geometric object Formula Condition
Triangles from n points C(n, 3) No three selected points are collinear
Segments joining n points C(n, 2) Each segment has two distinct endpoints
Diagonals of an n-gon n(n-3)/2 Polygon has n vertices
Chords from n circle points C(n, 2) Each chord joins two circle points
Maximum circle regions 1 + C(n, 2) + C(n, 4) No three chords are concurrent inside

Note: For collinear points, subtract selections that do not form the required geometric figure.

Hexagon vertices and diagonals

Visual guide: Hexagon vertices and diagonals
Number of vertices: n = 6 Total vertex pairs: C(6,2) = 15 Sides: 6 Diagonals: 15 - 6 = 9
A hexagon has 6 vertices, 15 total vertex pairs and 9 diagonals after its 6 sides are excluded.

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Quick Revision Notes

Geometry Based Permutation and Combination Revision Points

Use combinations for geometric selections because the order of selected points or segments generally does not matter.

  • Three non-collinear points form one triangle: C(n, 3).
  • If k points are collinear, subtract C(k, 3) invalid triangle selections.
  • Total segments joining n points: C(n, 2).
  • Diagonals of an n-gon: C(n, 2) - n = n(n-3)/2.
  • Chords joining n points on a circle: C(n, 2).
  • Maximum regions from all chords: 1 + C(n, 2) + C(n, 4), provided no three chords are concurrent inside.
  • Check whether the question asks for all selections or only selections satisfying conditions such as non-collinearity, non-adjacency or intersection.

Geometry Based Permutation and Combination FAQs

How many triangles can be formed from 10 points when no three points are collinear?

The number is C(10, 3) = 10 × 9 × 8 ÷ 6 = 120 triangles.

How many triangles are formed by the vertices of a 12-sided polygon?

Since no three vertices of a polygon are collinear, the number is C(12, 3) = 220.

What is the geometry based permutation and combination formula for diagonals?

For an n-sided polygon, diagonals = C(n, 2) - n = n(n-3)/2. The subtraction removes the n sides from all pairs of vertices.

How many diagonals does a 15-sided polygon have?

Diagonals = 15(15-3)/2 = 15 × 12 ÷ 2 = 90.

How many triangles can be formed from 8 points if 3 points are collinear and no other three are collinear?

Start with C(8, 3) = 56 and subtract the invalid collinear selection C(3, 3) = 1. Therefore, 55 triangles are formed.

How many chords can be drawn using 7 points on a circle?

Each chord is determined by two points, so the number is C(7, 2) = 21.

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